36x^2+74x+24=0

Solution for 36x^2+74x+24=0 equation:

36x^2+74x+24=0

a = 36; b = 74; c = +24;
Δ = b2-4ac
Δ = 742-4·36·24
Δ = 2020
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2020}=\sqrt{4*505}=\sqrt{4}*\sqrt{505}=2\sqrt{505}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-2\sqrt{505}}{2*36}=\frac{-74-2\sqrt{505}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+2\sqrt{505}}{2*36}=\frac{-74+2\sqrt{505}}{72}
$